Question

A batsman makes a score of 95 runs in the 13th match and thus increases his average runs per match by 4. What is his average after the 13th match?

A) 47 B) 43 C) 45 D) 49

Answer 1

Answer:

Taking his total score for 12 matches as x,

Avg. score for 12 matches will be:

$\frac{x}{12}$

The avg. increases by 4 after the 13th match. Also, as he had scored 95 runs in the 13th match, we get:

$( \frac{x}{12}) + 4 = \frac{(x + 95)}{13}$

Solving this further,

$\frac{(x + 48)}{12} = \frac{(x + 95)}{13} \\ (12)(x + 95) = (13)(x + 48) \\ 12x + 1140 = 13x + 624 \\ 1140 - 624 = 13x - 12x \\ 526 = x$

Thus, his score in the last 12 matches is 528 runs.

The avg. after the 13th match is:

$\frac{(x + 95)}{13} \\ = \frac{526 + 95}{13} \\ = \frac{621}{13} \\ = 47.76 \\ = approx. \: 47$

Hope this helps.

Thanks.

Answer 2

Answer:

Hello mate

Step-by-step explanation:

Your answer is a)47

plzz mark as brainliest or at least a thank you