Question

A batsman scored 40% of his total runs by sixes, 16% of his total runs by fours and rest by singles. If he scored 33 runs by singles, how many runs did he score by sixes?​

Answer 1

Answer:

he score 30 runs by sixes

Step-by-step explanation:

please mark it brainliest and folow me

Answer 2

$\huge\underline\bold{Answer:-}$

Given:-

Run% scored by sixes = 40%

Run% scored by fours = 16%

Run scored by singles = 33 Runs

To find:-

Runs scored by Sixes.

Solution:-

Let the total runs scored be 'x'.

As Per the Question,

Sixes% = 40% = $\dfrac{40}{100}\times{x}=\dfrac{10x}{25}$

Fours% = 16% = $\dfrac{16}{100}\times{x}=\dfrac{4x}{25}$

$\bold\pink{Total\:runs\:scored=(Runs\:scored\:by\:sixes+Runs\:scored\:by\:fours)= 33}$

$\implies{x}-(\dfrac{10x}{25}+\dfrac{4x}{25})$

$\implies{x}-[\dfrac{(10x+4x)}{25}]= 33$

$\implies{x}-(\dfrac{14x}{25})= 33$

$\implies\dfrac{(25x-14x)}{25}= 33$

$\implies\dfrac{11x}{25}= 33$

$\implies\dfrac{x}{25}= 3$

$\implies\:x-3\times25=75$

Numbers of Runs scored by Sixes= $\frac{10x}{25}=\frac{10(75)}{25}=\frac{750}{25}=30$