Question

A batsman strikes a ball with the speed of (2x-1)^3 km/h. What is the actual speed of the ball is px= 3x - 1/9.

Answer 1

Given:

The ball stricken with the speed of $(2x-1)^{3}$ km/h

To find:

The actual speed of the ball when it is expressed by $p(x)=\dfrac{3x-1}{9}$

Step-by-step explanation:

Now substitute $(2x-1)^{3}$ in place of $x$.

Then, $p(x)=\dfrac{3x-1}{9}$

$\Rightarrow p((2x-1)^{3})=\dfrac{3(2x-1)^{3}-1}{9}$

$\Rightarrow p((2x-1)^{3})=\dfrac{3(8x^{3}-6x^{2}+6x-1)-1}{9}$

$\Rightarrow p((2x-1)^{3})=\dfrac{24x^{3}-18x^{2}+18x-3-1}{9}$

$\Rightarrow p((2x-1)^{2})=\dfrac{24x^{3}-18x^{2}+18x-4}{9}$

Answer:

Actual speed of the ball is

$\dfrac{24x^{3}-18x^{2}+18x-4}{9}$ km/h

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