Question

A battery connected to a resistor supplies a current of 4A . If another resistor of equal resistance is connected in parrallel to the first resistor, the current supplied will be​

Answer 1

suppose the emf/voltage of the battery is V and the resistance connected to it is R

so from V=IR. V=4R

now when another resistor of equal resistance is connected in parallel to the first one the effective resistance becomes R/2

voltage is still V let the new current now be i

so V=iR/2

as V=4R

iR/2=4R

i=8 A

shortcut:

as resistance is halved and voltage is same the current will be doubled

Answer 2

Answer:

8 A

Explanation:

V/R =I

If resistance is halved,(as in parallel,) then voltage is constant, hence current would be doubled.