Question

A battery consists of 10 cells, each of emf 1V. If 2 cells are wrongly connected, how many emf of the battery becomes??​

Answer 1

Answer:

0.8

Explanation:

10cells=1emf

2cells=10-0.2=0.8

Answer 2

Given:

A battery consists of 10 cells, each of emf 1V.

To find:

Net EMF if 2 cells are wrongly connected ?

Calculation:

• Let's assume that the batteries have been connected in series combination in the circuit.

• However, among the 10 batteries, 2 batteries have been connected with opposite polarities (i.e. wrongly).

Now, net EMF will be :

$EMF = (1 + 1 + ...8 \: times) - 1 - 1$

$\implies EMF =8 - 2$

$\implies EMF =6 \: Volts$

So, net EMF of circuit is 6 Volts.