Question

A battery consists of 10 dry cells each of end 1.5V and internal resistance 0.5V the terminals of the battery are connected in a parallel combination of 3 omega and 5 omega find the current passing through battery

Answer 1

Answer:

8.5 V

Explanation:

Given: A battery of emf 10V and internal resistance 3Ω is connected to a resistor. The current in the circuit is 0.5A

To find the terminal voltage of the battery when the circuit is closed

Solution:

Emf of the battery, E=10V

Internal resistance of the battery, r=3Ω

Current in the circuit, I=0.5A

Resistance of the resistor = R

The relation for current using Ohm's law is,

I=

R+r

E

⟹R+r=

I

E

⟹R+r=

0.5

10

⟹R=20−3=17Ω

Terminal voltage of the resistor = V

According to Ohm's Law,

V=IR

⟹V=0.5×17

⟹V=8.5V

Therefore, the resistance of the resistor is 17Ω and the terminal voltage is 8.5V

Answer 2

Answer:

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