A battery having 12 V emf and internal resistence 3 is connected to a resistor. If the current in the circuit is 1A, then the resistence of resistor and lost voltage of the When circuit is closed will be.
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Answer:
I=RV
=I=3+R12
⇒3+R=12
R=9Ω
Terminal voltage =E−I
=12−3×1
=12−3=9V
Answer is (9,9)
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