Question

A battery is connected to a resistance causing a current of 0.5 A in the circuit. The current drops to 0.4 A when an additional resistance of 5 Ohms is connected in series. The current will drop to 0.2 A when the resistance is further increased by

Answer 1

Answer:

30 ohm

Explanation:

See the image for solutions Also

Answer 2

Answer: Resistance is further increased by 10 ohm

Explanation:

I = 0.5A when R = 0 ohm.............1

I(2) = 0.4A when R(2) = 5 ohm.....2

So, subtracting eq 2 from 1

We get 0.1A is decreased when 5 ohm is increased

0.3A........10 ohm i.e increased resistance by 5 ohms i.e 5+5=10 ohm

Therefore, for I = 0.2A, R = is increased by 10 ohm i.e 5+10=15 ohm