A battery is made by joining 36 cells the internal resistance of each cell is 4 ohm and its E.M.F is 2 volt.If the battery is used to obtain the maximum current in an external resistance 9 ohm then will you connect these in a battery also find the maximum current from the battery?
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Explanation:
12th
Physics
Current Electricity
EMF, Terminal Voltage and Internal Resistance and Problems on It
A battery of e.m.f 15 V and...
PHYSICS
A battery of e.m.f 15 V and internal resistance 3 ohm is connected to two resistors of resistances 3 ohm and 6 ohm in series. The p.d between the terminals of the battery is
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ANSWER
The total resistance of a circuit connected to the given cell of emf 15 V is the sum of all the resistances from various sources like, resistors, ammeter, voltmeter, etc., connected in series along with the internal resistance of the cell.
In
12th
Physics
Current Electricity
EMF, Terminal Voltage and Internal Resistance and Problems on It
A battery of e.m.f 15 V and...
PHYSICS
A battery of e.m.f 15 V and internal resistance 3 ohm is connected to two resistors of resistances 3 ohm and 6 ohm in series. The p.d between the terminals of the battery is
MEDIUM
Share
Study later
ANSWER
The total resistance of a circuit connected to the given cell of emf 15 V is the sum of all the resistances from various sources like, resistors, ammeter, voltmeter, etc., connected in series along with the internal resistance of the cell.
In this case, the total resistance is given as 3Ω+3Ω+6Ω=12ohms.
From the ohm's law the total current can be calculated from the formula I=V/R.
That is, I=
R
V
=
12A
15V
=1.25A.
Hence, the current through the battery is 1.25 amperes.
The voltage output of a device is measured across its terminals and is called its terminal voltage V. Terminal voltage is given by the equation V=emf−Ir where, r is the internal resistance and I is the current flowing at the time of the measurement.
Therefore, V=15V−(1.25×3)=11.25V.
Hence, the potential difference across the terminals of the cell is 11.25V this case, the total resistance is given as 3Ω+3Ω+6Ω=12ohms.
From the ohm's law the total current can be calculated from the formula I=V/R.
That is, I=
R
V
=
12A
15V
=1.25A.
Hence, the current through the battery is 1.25 amperes.
The voltage output of a device is measured across its terminals and is called its terminal voltage V. Terminal voltage is given by the equation V=emf−Ir where, r is the internal resistance and I is the current flowing at the time of the measurement.
Therefore, V=15V−(1.25×3)=11.25V.
Hence, the potential difference across the terminals of the cell is 11.25V