Question

A battery is used to charge a parallel plate capacitor till the
potential difference between the plates becomes equal to
the electromotive force of the battery. The ratio of the
energy stored in the capacitor and the work done by the
battery will be
(a) 1/2 (b) 1 (c) 2 (d) 1/4

Answer 1

Answer:

(a) 1/2

Explanation:

Let, potential difference between plates = V

emf of battery = ε

here, V = ε

Energy stored in the capacitor is U = 1/2 CV²

Work done by battery is W = qε = (Cε)ε = Cε² = CV²

∴  W/U =   1/2

HOPE IT WILL HELP UH...