Physics, asked by aroraradhs1221, 1 year ago

A battery of 10 volt carries 20000 coulomb of charge through a resistance of 20 ohm . The work done on 10 seconds will be what?

Answers

Answered by gadakhsanket
35

Dear Student,

◆ Answer -

W = 50 J

● Explanation -

# Given -

V = 10 V

Q = 20000 C

R = 20 ohm

t = 10 s

# Solution -

Work done by the battery is -

W = V²t/R

W = 10^2 × 10 / 20

W = 100 × 1/2

W = 50 J

Hence, the work done on 10 seconds will be 50 J.

Thanks dear. Hope this helps you...

Answered by iimpu1386
35

Answer:

2×10^5

Explanation:

l= Q/t

l=20000/10

l=2000amphere

p=10×2000

This power will be 20000w of J/S

Now work done Will be-

W=20000×10

W=2×10^5J

Thus work done by the battery will be 2×10^5

I HOPE THIS IS HELP TO U

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