Question

A battery of 10v carries 20,000C of the charge through a resistance of 20ohm find the work done in 10seconds

Answer 1

The work done by the charged particle is $2\times 10^5\ J$.

Explanation:

Given that,

Voltage of the battery, V = 10 volt

Charge, q = 20,000 C

Resistance, R = 20 ohms

Time, t = 10 s

We need to find the work done by the charged particles. It is given by :

$W=qV$

$W=20000\ C\times 10\ V$

$W=2\times 10^5\ J$

So, the work done by the charged particle is $2\times 10^5\ J$. Hence, this is the required solution.

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Answer 2

Given that,

Voltage of the battery, V = 10 V

Charge, q = 20,000 C

Resistance, R = 20 ohms

To find,

Work done in 10 seconds.

Solution,

Current flowing in 10 seconds is :

$I=\dfrac{q}{t}\\\\I=\dfrac{20000}{10}\\\\I=2000\ A$

Work done by battery is given by :

$W=V\times q\\\\W=10\times 20000\\\\W=2\times 10^5\ J$

So, the work done by the battery is $2\times 10^5\ J$.

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