Question

a battery of 12 v is connected in series with 2 and 6 ohm resistor calculate the current through the circuit and the voltage across 6 ohm resistor​

Answer 1

Answer:

Resistance 2 and 6 Ω are connected in series hence equivalent resistance between them will be

Req = R1 + R2

Req = 2 + 6

Req = 8 Ω

We know that current flowing through a conductor is directly proportional to potential difference across it

V = RI

12 = 8×I

I = 1.5 A

Hence the voltage across 6 ohm resistor

V = RI

V = 6×1.5

V = 9 v

Answer 2

Given :

➾ Two identical resistors of resistances 2Ω and 6Ω are connected in series with a battery.

➾ Voltage of battery = 12V

To Find :

➳ Current through the circuit.

➳ Pd across 6Ω resistor.

Concept :

➠ Equivalent resistance of series connection is given by

• R = R¹ + R²

➠ As per ohm's law, current flow through resistor is directly proportional to the applied potential difference.

Mathematically, V = IR

➠ We know that, current flow through each resistor in series connection remains same.

Calculation :

✴ Current flow in circuit :

⇒ V = I × Req

⇒ V = I × (R¹ + R²)

⇒ 12 = I × (2 + 6)

⇒ I = 12/8

⇒ I = 1.5A

✴ Pd across 6Ω resistor :

⇒ V = I × R

⇒ V = 1.5 × 6

⇒ V = 9 volt