Question

A battery of 12 V is connected in series with resistors of 0.2Ω, 0 .3 Ω, 0.4, Ω, 0.5 Ω and 10 Ω, respectively. How much current would flow through the 10 Ω resistor?
Draw circuit diagram with the above components and an ammeter and a voltmeter across the resistor 10 Ω

Answer 1

12 volt only

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Answer 2

Given:

A battery of 12 V is connected in series with resistors of 0.2Ω, 0 .3 Ω, 0.4, Ω, 0.5 Ω and 10 Ω, respectively.

To find:

How much current would flow through the 10 Ω resistor?

Solution:

From the given information, we have the data as follows.

A battery of 12 V is connected in series with resistors of 0.2 Ω, 0 .3 Ω, 0.4, Ω, 0.5 Ω and 10 Ω, respectively.

In the series connection of resistors, the current remains constant.

Firstly, we will compute the series resistance.

R_s = 0.2 + 0.3 + 0.4 + 0.5 + 10

R_s = 11.4 Ω

Now, we will compute the value of the current.

I = V/R_s

I = 12/11.4

I = 1.05 A

Therefore, the current through the resistor 10 Ω is 1.05 A.