A battery of 12 v is connected to a series combination of resistors 3 ohm,4 ohm,5 ohm and 12 ohm. How much current would flow through the 12w resistor
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A battery of 12v i.e., V=12v
R series =R1+R2+R3+R4
". 3+4+5+12=24OHM
V=12v
I=V/R
I=12/24 = 1/2 OR 0.5 ampere
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R series =R1+R2+R3+R4
". 3+4+5+12=24OHM
V=12v
I=V/R
I=12/24 = 1/2 OR 0.5 ampere
mark it as brainliest please
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