a battery of 12 volt is connected to a series combination of resistors 3Ω , 4Ω , 5Ω and 12Ω. how much current would flow through the 12Ω resistor?
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Answered by
8
total resistance=3+4+5+12=24ohm
net current=12/24=0.5A
since, it is a series combination,same current flows through all resistances
thus current through 12ohm resistor=0.5A
net current=12/24=0.5A
since, it is a series combination,same current flows through all resistances
thus current through 12ohm resistor=0.5A
Answered by
5
R = 3 + 4 + 5 + 12 = 24 Ohm
V = 12 volt
I = V/R
= 12 / 24
= 0.5 A
Current in a series combination doesn’t change. Hence current passing through 12 Ohm resister is 0.5 A
V = 12 volt
I = V/R
= 12 / 24
= 0.5 A
Current in a series combination doesn’t change. Hence current passing through 12 Ohm resister is 0.5 A
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