a battery of 12 volt is connected to a series combination of resistance 3 ohm 4 ohm 5.12 how much current would flow through the 12 ohm resistor
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❃ Heya....friend....❃
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☛Here is your answer :------
☑️Given,
___________V = 12v__________
___________R1 = 3 ohm________
___________R2 = 4 ohm_________
___________R3 = 12ohm__________
◼️Now,
Total resistance would be =====>
R= 3 + 4 + 12
= 19 ohms
⚫Then, according to formula---------
V = I R
I = V / R
☛And we know it is a series combination, and current will be similar in all resistance.
That's why, the current will be in 12 ohm =====>
I = 12/19
☑️I = 0.63A
Hope it will help you!
Thanks!!☺️
============
==================
☛Here is your answer :------
☑️Given,
___________V = 12v__________
___________R1 = 3 ohm________
___________R2 = 4 ohm_________
___________R3 = 12ohm__________
◼️Now,
Total resistance would be =====>
R= 3 + 4 + 12
= 19 ohms
⚫Then, according to formula---------
V = I R
I = V / R
☛And we know it is a series combination, and current will be similar in all resistance.
That's why, the current will be in 12 ohm =====>
I = 12/19
☑️I = 0.63A
Hope it will help you!
Thanks!!☺️
============
ankitsagar:
nice dear
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