Question

A battery of 12 volts is connected to two resistors of 6 ohm and 4 ohm
joined together in series. Find the potential drop across each
resistor respectively?
А. 3.7 V ... 2.5 V
B. 5.9 V ... 3.1 V
C. 7.2 V ... 4.8 V
D. 8.1 V ... 5.3 V
E. 9.7 V ... 7.7 V
ܐܶ​

Answer 1

Answer:

C. 7.2 V ... 4.8 V

Explanation:

R₁ + R₂ = $R_{comb}$ (When resistors are connected in series, the combined          resistance is expressed as the sum of individual resistors. )

⇒ $R_{comb.}$= 6Ω + 4Ω = 10Ω

Voltage = 12 V

Current flowing through the circuit (I) = $\frac{V}{R_{comb} }$

                                                              =$\frac{12}{10}$ A = 1.2 A

Voltage across 6Ω resistor = R*A = 6Ω * 1.2 A

                                             = 7.2 V

Voltage across 4Ω resistor = R*A = 4Ω * 1.2 A

                                             = 4.8 V