A battery of 12V is connected in parallel with three resistors of each of 2π resistance.How much current will flow through them?-------please help
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Answered by
3
Answer:
use kirchoffs law(KVL)....
Answered by
1
Answer:
18A
Explanation:
since they are connected in parallel potential drop across them is same I.e.12V
current through each resistor
i=12/2=6A
total current=6+6+6=18A
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