Question

A battery of 12V is connected in parallel with three resistors of each of 2π resistance.How much current will flow through them?-------please help​

Answer 1

Explanation:

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/2 + 1/2 + 1/2

1/R = 1+1+1/2

1/R = 3/2

R = 2/3

R = 0.6 ohm

I = V/R

= 12/0.6

= 20 A

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Answer 2

total resistance (1/R) = 1/2π +1/2π +1/2π

1/R = 3/2π

1/R= 3/2π

R = 2π/3

current= volt/resistance

= 12 / 2π/3

= 12× 3/2π

= 6× 3π

= 18 π Amp