Question

A battery of 12V is connected in series with resistors of 0.2 ohm, 0.3 ohm, 0.4 ohm, 0.5 ohm and 12 ohm.

How much current would flow through the 0.3 ohm resistor?​

Answer 1

Answer:

Here is your answer 1.11A

Answer 2

Answer:

0.895

Explanation:

It is given that

R1 = 0.2 Ω

R2 = 0.3 Ω

R3 = 0.4 Ω

R4 = 0.5 Ω

R5 = 12 Ω

R = R1 + R2 + R3 + R4 + R5

R = (0.2 + 0.3 + 0.4 + 0.5 + 12)Ω

R = 13.4 Ω

According to Ohm's Law

V = IR

Here V is 12 V and R is 13.4 Ω

Now I = V/R

I = 12/13.4

I = 0.895522388 = 0.895

All resistors are connected in series. So, the current will be same in all resistors

Hence current flow through the 0.3 ohm resistor is 0.895 A

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