Question

A battery of 12V is connected to a series combination of resistors 3ohm,4ohm,5ohm and 12ohm.how much current would flow through the 12ohm resistor?

Answer 1

Answer:

series

Rs=R1+R2+R3

3+4+5+12=24

V=IR

I=V/R

I=24/12

I=2

the current flow is 2A

Answer 2

Answer:

Hay mate there is ans

Voltage =12V

12ohm resistance given and in Q current is ask of 12ohm resistor .so we take only 12ohm resistance.

SO

I=V/R

I=12V/12ohm

I=1

hence , current is 1 Amper ...

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