Question

A battery of 12V is connected to a series combination of resistors 3 ohm , 4 ohm , 5 ohm and 12 ohm . How much current wud flow thru de 12 ohm resistor?​

Answer 1

just simply apply kvl on the circuit

Explanation:

12v=I(R1+R2+R3+R4)

12V=I(4+3+5+12)

12V=I(24)

I=0.5