Physics, asked by jayantimandal2004, 19 days ago

A battery of 15 volt and negligible internal resistance is connected across a 50 ohm resistor. The amount of energy dissipated as heat in 1 minute?

Please give exact answer urgent
otherwise I'll report

Answers

Answered by nasreenmulla40

0

Answer:

According to formula. V= R I. SO. I= V/R where v voltage, i current ,, R resistance.. SO I = 6/5 = 1.2 For energy dissipated , Use R= I*V .

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