Question

A battery of 15 Volt is connected to a parallel grouping of resistance 9 Ω, 18 Ω and 6 Ω. Find the

current drawn through the battery.​

Answer 1

Explanation:

Resistance = volt / current

current = volt / resistance

Given resistance are 9, 18, 6

current = 15/9 = 5/3 Ampere

current = 15/18 = 5/6

Current = 15/6 = 5/2

Answer 2

Explanation:

net R=(9×18×6)/9+18+6

R=324/11

V/R=I

=15×11/324

I=55/108ampere