Question

A battery of 20000 coulomb of charge through a resistence of 20. the work done in 10seconds​

Answer 1

Answer:

$\pink{ \boxed{\boxed{\begin{array}{cc} \maltese  \bf \: \: given \\ \\ \odot \sf \: \: charge \: \: q = 20000 \:C \\ \\ \odot \sf \: resistance \: \: R = 20 \: ohm \\ \\ \odot \sf \: time \: \: \: t = 10 \: s \\ \\ \ \bigstar \sf \: work \: \: W = \: to \: find \\ \\ \bf \: we \: know \: that \\ \\ \sf \: W = Vq \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf = IRq \: \: \: \: \{ \: V = IR \} \\ \sf = \frac{q}{t} \times Rq \: \: \: \{I = \frac{q}{t} \} \\ \\ \sf = \frac{20000}{10} \times 20 \times 20000 \\ \\ =8 \times {10}^{8} \: J \end{array}}}}$