Question

A battery of 3cells in series each of emf 2 volts and internal resistance 0.5ohms is connected to a 2ohm resistor in series with a parallel combination two 3ohms resistor

Answer 1

Answer:

Effective resistance=R

Total resistance of circuit will be

R=2ohm +3×3\3+3ohm= (2+1.5)ohm=3.5

Equivalent resistance of the circuit Req= (3.5+1.5)=5ohm

Emf cell

V=E1+E2+E3=(2+2+2)v=6v

2. Current the circuit

=E/Req=6/5A

3. Lost voltage=v=Ir=6/5×1.5=1.8v

4. Current in the 3ohm resistor

(I1) =6/5×2=0.6A.

Hope it was helpful

Explanation:

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