Question

A battery of 6.7V is connected in series with resisters of 0.1 ohm , 0.15 ohm,0.2 ohm,0.25 ohm and 6 ohm. How much current would flow through the 6 ohm resistor

Answer 1

AnsWer :

1 A.

Given :

• R1 = 0.1 ohm.
• R2 = 0.15 ohm.
• R3 = 0.2 ohm.
• R4 =0.25 ohm.
• R5 = 6 ohm.
• Connected in Series Connection.
• Battery give 6.70 V.

Concepts Required :

• Series Combination - When Resistors connected in only one path or follow only path, it said to be Series Connection.

• In Series Connection Current are some but Voltage are different in each resistor.

• Parallel Connection - When Resistors connected in two or more or follow two or more path it, said to be Parallel Connection.
• In parallel Connection Current are different in each resistor and Voltage are same.

Solution :

We have,

Formula for Series Connection.

$\tt R_s = R_1 +R_2 +R_3 + R_n.$

$\tt\dashrightarrow 0.1 + 0.15 + 0.25 + 0.2 + 6.$

$\tt\dashrightarrow 6.70 \: \Omega.$

Now, According to Ohm' s.

$\tt \large V = IR.$

$\tt\dashrightarrow 6.70 = I.6.70.$

$\tt\dashrightarrow I = 1 \: A.$

In Series Connection Current flow same.

Therefore, current flow in 6 ohm resistor be 1 A.

Answer 2

Answer:

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