A battery of 6 V is connected in series with resistors of 1Ω, 2Ω and 3Ω. How much current will flow through 2 Ω resistor? (a) 2 A (b) 1A (c) 3 A (d) 6 A
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(b) 1A
Explanation:
we given that v=6volt ,Resistence,r=R1+R2+R3=6ohm
we know that I=V/R=6/6=1A
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