Question

A battery of 6 volt is connected to the terminal of a three meter long wire of uniform thickness and resistance of 100 ohm the potential difference between two Points separated by 50 cm on the wire

Answer 1

Answer:

according to given parameter in question

R=P 1/A

=100 =P 3/ 1

=P/A =100/ 3

thus total resistance. of 50 cm wire is

R1 =P / A L = 100/3 ×0.5 =50/3

the total current in the wire is I =6/100=A

therefore potential difference across the 2 point on the wire separated by a distance of 50 m is

( v ) ,= 1R1 = 50/3 ×6/100=1v

ART BY ZEENATH PRINCESS