Question

A battery of 6v is connected in series with resisters of 0.1 ohm , 0.15 ohm, 0.2 ohm, 0.25 ohm and 6 ohm. how much current would flow through the 0.3 ohm resistor? solution

Answer 1

Given,
V=6v
Total resistance= 0.1+0.15+0.2+0.25+6=6.70
we have to find the current flow through 0.3 ohms
So,
I=V/R
I=6/0.3=20ampere

Answer 2

Given:

Voltage = 6v

Resistors 0.1Ω, 0.15Ω, 0.2Ω, 0.25Ω, 6Ω

To Find:

current through 0.3Ω

Solution:

we know,

Equivalent resistance = 0.1 + 0.15 + 0.2 + 0.25 + 6 = 6.70 Ω (as all are in series)

V = IR

I = V/R

current through 0.3 Ω resiatance

I = 6 / 0.3 = 20 A

So,current through 0.3 resiatance =20 A