. A battery of 6V is connected in series with resisters of 0.2 ohm , 0.15 ohm,0.4 ohm,0.25 ohm and 2 ohm. How much current would flow through the 0.2 ohm resistor? *
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Answer:
Given,
V=6v
Total resistance= 0.1+0.15+0.2+0.25+6=6.70
we have to find the current flow through 0.3 ohms
So,
I=V/R
I=6/0.3=20ampere
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2.5 A
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