A battery of 6V is connected in series with resistors of 0.1,0.15,0.2,0.25 and 6 ohm. How much current would flow through the 0.3 ohm resistor ?
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Answer:
Potential difference= 6 V
Total resistance=0.1+0.15+0.2+0.25+6=6.70 ohm
New resistance=0.3 ohm
By applying ohm's law
V=IR
6= I x 0.3
I= 6/0.3=6/3/10
I=6 x 10/3= 20 A
Explanation:
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