Question

A battery of 6V is connected in series with resistors of 0.1,0.15,0.2,0.25 and 6 ohm. How much current would flow through the 0.3 ohm resistor ?

Answer 1

Answer:

Potential difference= 6 V

Total resistance=0.1+0.15+0.2+0.25+6=6.70 ohm

New resistance=0.3 ohm

By applying ohm's law

V=IR

6= I x 0.3

I= 6/0.3=6/3/10

I=6 x 10/3= 20 A

Explanation: