a battery of 9 V is connected in series with resistors of 0.2 ohm, 0.3 ohm,0.4 ohm, 0.5 ohm and 12 ohm respectively how much current will flow through 12 ohm resistor
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Answer:
0.75
Explanation:
I = V/R
= 9/12
= 3/4
= 0.75
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