Physics, asked by Barbie01, 1 year ago

A battery of 9 V is connected in series with resistors of 0.2ohm,0.3ohm,0.4ohm,0.5ohmand12ohm. How current would flow through the 12ohm resistor?

Answers

Answered by priyanka131

current will remain same in all resistors because these resistors are connected in series.

Barbie01: ans is 0.67A

priyanka131: Ya ans. is correct

priyanka131: firstly u have to add all resistors 0.2+0.3+0.4+0.5+12=13.4,.after this apply the formula of current I. e. I =v /R and put the values I =9/13.4=0.671.

Barbie01: thanku so much

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