A battery of 9 V is connected in series with resistors of 0.2ohm,0.3ohm,0.4ohm,0.5ohmand12ohm. How current would flow through the 12ohm resistor?
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current will remain same in all resistors because these resistors are connected in series.
Barbie01:
ans is 0.67A
Ya ans. is correct
firstly u have to add all resistors 0.2+0.3+0.4+0.5+12=13.4,.after this apply the formula of current I. e. I =v /R and put the values I =9/13.4=0.671.
thanku so much
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