Question

A battery of 9 V is connected in series with resistors of 0.2 Ohms, 0.3 Ohms, 0.4 Ohms and 0.9 Ohms respectively

Find out
Amount of the current flow through the 9 Ω resistors​

Answer 1

Answer:

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω, and 12 Ω, respectively. How much current would flow through the 12 Ω resistor? Thus, Current through 12 Ω resistor = 0.67 A.

Step-by-step explanation:

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Answer 2

Answer:

5 Amperes

Step-by-step explanation:

Net resistance $R_{net} = 0.2 + 0.3 + 0.4 + 0.9 = 1.8$ Ohm

Current = $\frac{V}{R} = \frac{9}{1.8} = 5 A$ by Ohm's Law