Physics, asked by Abhishek3246, 5 days ago

A battery of 9 V is connected in series with resistors of 2ohm,3ohm,4ohm and 5ohm respectively.
Calculate the current flowing in the circuit.
Draw the circuit diagram.

Answers

Answered by sn62581

0

Answer:

I=9/14

Explanation:

in series connection current I is constant

v=I(r1+r2+r3+r4)

I=v/r1+r2+r3+r4

I=9/14

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