Physics, asked by Abhishek3246, 1 month ago

A battery of 9 V is connected in series with resistors of 2ohm,3ohm,4ohm and 5ohm respectively.
Calculate the current flowing in the circuit.
Draw the circuit diagram.

Answers

Answered by sn62581

0

Answer:

I=9/14

Explanation:

in series connection current I is constant

v=I(r1+r2+r3+r4)

I=v/r1+r2+r3+r4

I=9/14

Previous Question

Next Question

Similar questions

Hindi, 25 days ago

जब कोई पंचमाक्षर द्वित्व रूप में आए तो ------का प्रयोग नहीं होगा...

Political Science, 25 days ago

Is it througfare (tell Punjabi)...

Hindi, 25 days ago

हिम्मत करने वालों की हार नहीं होती’ कविता के अनुसार गोताखोर सिन्धु में डुबकियाँ क्यों लगाता है?मनोरंजन के लिए मोतियों के लिए खेलने के लिए नहाने के लिए...

English, 1 month ago

0 points It was the most difficult situation.(change into 'comporative Degree') It was more difficult than any other situation. It was as difficult as any other situation. O Very few situations are as difficult as it. O None of the above.

English, 1 month ago

A man who tqkes away another mam's freedom is?

Accountancy, 9 months ago

EX Journal 2. Enter the following transactions in the Journal of Ram: Any 2020 June June of 1 Ram invested capital in cash 3 Purchased goods from Harish June 5 Purchased goods for cash June 8 Purchased goods from Mohit for cash June 10 Sold goods to Kailash on credit June 12 Sold goods to Nadeem for cash June 14 Goods returned by Kailash June 16 Goods returned to Harish June 18 Machinery...

Math, 9 months ago

Find the product in each case (a) 5613 x 0...

Math, 9 months ago

Let X1, X2, X3, be terms of an AP, if Xy+X2 +...+X, x₂ + x₂ + =? (n + m), then *8 X 23 2 .+X m 1 3 O 3 1 9 O 9...