Question

A battery of 9 v is connected un series with resistor of 0.2 0.3 0.4 0 5 and 12 respectively .how much current would flow through the 12 resistor

Answer 1

Answer:

V=9v

R=0.2+0.3+0.4+0.5+12=13.4ohm

I=V÷R

I=9÷13.4 =0.67 ampere

so a current of 0.67 A will flow through the 12 ohm resistor