Question

a battery of 9 volt is connected in series resistors of 0.2 ohm 0.3 ohm 0.4 ohm 0.5 ohm and 12 ohm respectively how much current will flow through 12 ohm resistor

Answer 1

V=IR
9volt=I×13.5ohm(total resistance)
i=9/13.5
i=90/135
i=0.666666667
It is the total current in the circuit and because all resistors are in series then current in 12 ohm resistor is also 0.6666667 Ampere.

Answer 2

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Total resistance of resistors when connected in series is given by

= 1 + 2 + 3 + 4 + 5

= 0.2 Ω+ 0.3 Ω+ 0.4 Ω+ 0.5 Ω+ 12 Ω = 13.4 Ω

According to Ohm’s law,

V = IR

I =V/R

I = 9 /13.4 = 0.67

▶▶There is no current division occurring in a series circuit.

So, the current through the 12 Ω resistor will be same as 0.67 A.

I hope, this will help you___❤❤

Thank you

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