a battery of 9 volt is connected in series with resistor 0.3 ,0. 4, 0.5 0.2 ohm respectively how much current will flow through 12 ohm register
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Answered by
0
R=total=1.4ohm,9=1.4×I=,|=45/7,v=r×i
adsri:
90 ans 80 is wrong
sorry
Answered by
1
R=R1 plus R2 plus R3 plus R4 plus
0.2 + 0.3 + 0.4 + 0.5
1.4
R = V upon I
9 upon 1.4
6.42857143
6.43
0.2 + 0.3 + 0.4 + 0.5
1.4
R = V upon I
9 upon 1.4
6.42857143
6.43
Sorry then I = V upon i
not i but R
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