Question

a battery of 9 volt is connected in series with resistor of 0.2 ohm 0.3 ohm 0.4 ohm 0.5 ohm and 12 ohm respectively how much current will flow through the 12 volt resistor

Answer 1

potential difference = v = 9v

Current = I = ?

Total resistance = Rs = ?

Total resistance = Rs = 0.2 ohm + 0.3 ohm + 0.5 ohm + 12 ohm = 13 ohm

v = IRs

v/Rs = I

9/13 = I

0.69 A = I  ( ≈ )

when resisters are connected in series then same amount of current flow through each resistor

so, 0.69 ampere current flow through 12 ohm resistor

Answer 2

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Total resistance of resistors when connected in series is given by

= 1 + 2 + 3 + 4 + 5

= 0.2 Ω+ 0.3 Ω+ 0.4 Ω+ 0.5 Ω+ 12 Ω = 13.4 Ω

According to Ohm’s law,

V = IR

I =V/R

I = 9 /13.4 = 0.67

▶▶There is no current division occurring in a series circuit.

So, the current through the 12 Ω resistor will be same as 0.67 A.

I hope, this will help you___❤❤

Thank you

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