Question

A battery of 9 Volt is connected in series with resistors of 2 ohms, 7 ohms, 4 ohms and 5 ohms.
How much current will flow through the 7 ohms resistor?

Answer 1

0.5 A is the current flowing through the 7 Ω  resistor.

Explanation:

Given that,

V = 9

$R_{1}$ = 2  Ω  

$R_{2}$ = 7  Ω  

$R_{3}$ = 4  Ω  

$R_{4}$ = 5  Ω  

To find,

Current flowing through 7 ohms resistor = ?

So,

$R_{eq}$ = $R_{1}$  + $R_{2}$  + $R_{3}$ + $R_{4}$

= 2  Ω + 7  Ω + 4  Ω + 5  Ω

= 18 Ω

As per Ohm's law,

V = I$R_{eq}$

9 = I * 18 Ω

∵ I = 0.5 A

The same current flows similarly across all the transistors in a series. Thus, the current flowing through the 7 Ω  resistor = 0.5 A

Learn more: Ohm's law

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