a battery of 9 volt is connected in series with resistors of 0.2ohm,0.4ohm,0.3ohm,0.5
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A battery of 9V is connected in series with resistors of 0.2 ohm, 0.3 ohm, 0.4 ohm, 0.5 ohm and 12 ohm, respectively. How much current would flow through the 12 ohm resistor? Equivalent resistance in series = 0.2 + 0.3 + 0.4 +0.5 + 12 =13.4 ohms.
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