Question

a battery of 9 volt is connected in series with the resistance of 0.2 ohm 0.3 ohM 0.5 ohm and 12 ohm respectively how much current will flow through the 12 resistor

Answer 1

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All the resistors are connected in series .so,
combined resistance,R = 0.2 +0.3 +0.4 + 0.12
= 13.4
Potential difference,V = 9 V
Current, I = ?
current flowing the whole circuit can be calculated by using Ohm 's law :
V/I = R
9/I = 13.4
I = 9/13.4
current , I = 0.67 A

Since the same current flows through all resistors connected in series in a circuit , therefore , 0.67 ampere of current would flow through the 12 ohms resistor.

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Answer 2

I hope this will help you