Question

a battery of 9 volts is connected in series with resistors of 0.2 ohm, 0.3 ohm, 0.4 mm, 0.5 mm and 12 ohm respectively how much current will flow through the 12 ohm resistor

Answer 1

In series combination, the current(I) remains same.

So , by using the formula V=IR

I=V/R

I=9/12

I=0.75A

Hope it helps.

Answer 2

0.72 ampere current follow bcoz its in series.