Question

A battery of 9v is connected in series with resistors of 0.2,0.3,0.4,0.5and12ohm respectively how much current would flow through the 12ohm resistor

Answer 1

Answer:

Given ;

p. d = 9V

Total resitance(R) = {R¹ +R²+ R³+ R⁴ + R5}

Total resistance (R) = {0.2 + 0.3+ 0.4 + 0.5 + 12}

Total resistance (R) = 13.4 ohm

current (I) = ?

•°• I = V/R

I = 9/13.4

I = 0.67 Ohm

{ Note, curent through all the resistors of a series combination of reaiators is equal}