Question

a battery of 9V is connected in series with resistors of 0.2 ohm,0.3 ohm,0.4 ohm,0.5 ohm and 12 ohm,respectively .how much current would flow through the 12 ohm resistor

Answer 1

When we connect in series,

Pottential difference wiil be different across each resistor

And current will be equal across each resistor

So,

Total current in the circuit = current flowing throw each resistor

Total current in the circuit = voltage / resistance

I = V/R

Total resistance = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4

Voltage = 9V

Current = 9/13.4 = 0.67

Hope this will help...

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