Question

A battery of 9v is connected in series with resistors of 0.2ohm,0.3ohm,0.4ohm,0.5ohm and 12ohm.How much current would flow through 12ohm resistor.

Answer 1

ANSWER :-

★ Given:-

• V = 9 V

★ Calculation:-

R = 0.2  +  0.3  +  0.4  +  0.5  +  12

==> R = 13.4 ohm.

We know that,

• I = V / R

Substituting the values,

I = 9 / 13.4

Therefore, I = 0.67 A

We know that,

In series, current is equally distributed in all the resistors.

Hence, 0.67 A current would flow through 12 ohm resistor.

Answer 2

Total resistance of resistors when connected in series is given by -

$\small\tt\red{R=R1+R2+R3+R4+R5}$

$\small\tt\red{R=0.2+0.3+0.4+0.5+12}$

$\small\tt\red{13.4\mho}$

$\large\mathbb\purple{A/C,OHM'S\:LAW,}$

$\large\mathbb\purple{V=IR}$

$\large\tt\green{I=\frac{V}{R}=\frac{9}{13.4}=0.67A}$

There is no current division occurring in a series circuit. So, the current through the 12 ohm resistor will be same as 0.67A