a battery of 9v is connected in series with resistors of 2 ohm 0.3 ohm and 0.5 ohm and 0.12 ohm respectively . how much current would flow through the 12 ohm resistors
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I=V/R, so
total resistance=(2+0.3+0.5+12)ohm=14.8ohm
•.•V is 9volt, I=9/14.8=0.608
so current through 12ohm resistor will be same as that in the circuit
=>current through 12ohm resistor is 0.608
SEE THE BRAINLIEST ANSWER
total resistance=(2+0.3+0.5+12)ohm=14.8ohm
•.•V is 9volt, I=9/14.8=0.608
so current through 12ohm resistor will be same as that in the circuit
=>current through 12ohm resistor is 0.608
SEE THE BRAINLIEST ANSWER
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