a battery of 9v is connected in series with resistors of0.2,0.3,0.4,0.5,&12ohm.how much current would flow through the 12ohm resistor?......
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Answered by
10
Given,
Voltage, V = 9v
Since, the resistors are in series.
Thus,
Total resistance,R = 0.2+0.3+0.4+0.5+12 = 13.4 ohm
Thus,
V = IR
9 = I × 13.4
I = 9/13.4 = 0.67 A
Voltage, V = 9v
Since, the resistors are in series.
Thus,
Total resistance,R = 0.2+0.3+0.4+0.5+12 = 13.4 ohm
Thus,
V = IR
9 = I × 13.4
I = 9/13.4 = 0.67 A
snehashashi:
thanks
Answered by
2
Answer:
the answer is in the back of the textbook and another guy already answered so u can take reference or go to teachoo or vedantu to know with steps.............
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